# CBSE Class 10 Mathematics Coordinate Geometry MCQ

CBSE CLASS 10 MATHEMATICS / MCQ | Multiple Choice Questions/ COORDINATE GEOMETRY – Chapter 7

1. The distance of a point from the y axis is called its —————

A. Ordinate
B. Abscissa
C. Origin

2. The distance of a point from the x axis is called its ——————

A. Ordinate
B. Abscissa
C. Origin

3. The coordinates of a point on the x axis are of the form —————

A. (0, x)
B. (x, 0)
C. (y, 0)

4. The coordinates of a point on the y axis are of the form———–

A. (0, y)
B. (y, 0)
C. (x, 0)

5. A linear equation in two variables of the form ax + by + c = 0, when represented graphically gives a ——————

A. Parabola
B. Circle
C. Straight line

6. The graph of a quadratic equation is a —————

A. Parabola
B. Circle
C. Straight line

7. The relation between x and y such that the point (x, y) is equidistant from the points (7, 1) and (3, 5) is —————–

A. x + y =2
B. x – y = 2
C. y – x = 2

8. The area of a triangle whose vertices are (1, -1) (-4, 6) and (-3, -5) is ———-

A. 20
B. 22
C. 24

9. The value of k if the points A (2, 3), B (4, k) and C (6, -3) are collinear is —————-

A. 0
B. 2
C. 4

10. The distance between the points A (1, 1) and B (9, 7) is —————-

A. 8
B. 9
C. 10

11. The points (1, 7) (4, 2) (-1, -1) and (-4, 4) are the vertices of a —————–

A. Rectangle
B. Square
C. Parallelogram

12. The points (5, -2) (6, 4) and (7, -2) are the vertices of an ————– triangle.

A. Scalene
B. Equilateral
C. Isosceles

13. The distance of a point P (4, 3) from the origin (0, 0) is given by ————–

A. 3
B. 4
C. 5

14. The points (3, 2) (-2, -3) and (2, 3) form a ———— triangle.

A. Acute angle
B. Right angle
C. Obtuse angle

15. A point on the y axis which is equidistant from the points A (6, 5) and

B (-4, 3) is —————-
A. y = 8
B. y = 9

C. y = 10

1. Abscissa
2. Ordinate
3. (x, 0)
4. (0, y)
5. Straight line
6. Parabola
7. x – y =2 (Use distance formula)
8. 24. (Use the formula for Area)
9. k = 0
Since the given points are collinear the area of the triangle formed by them must be zero.
½ [2(k +3) + 4(-3-3) + 6(3 –k)] = 0
½ [-4k] = 0
k = 0
10. 10 (Use distance formula)
11. Square
Let A (1, 7), B (4, 2) C (-1, 1) and D (-4, 4) be the given points. Using distance formula, find the length of the sides AB, BC, CD, AD and diagonals AC and BD.
All the four sides of the quadrilateral ABCD are equal and its diagonal AC and BD are also equal. Therefore, ABCD is a square.
12. Isosceles triangle
13. 5
14. Right triangle
15. y = 9
A point on the y axis is of the form (0, y). So let the point P (0, y) is equidistant from A and B. Then find the distance between (0, y), (6, 5) and (0, y), (-4, 3) then equate.