# CBSE Class 6 Mathematics Worksheets/Part 4/Half Yearly Examination

**CBSE Class 6 Mathematics Worksheets is about some model questions that you can expect for half yearly examination. Here you can find out practice problems for class 6 Mathematics.**

**CBSE CLASS 6 MATHEMATICS WORKSHEETS/ Part 4/ Half Yearly ExaminationChoose the correct answer from the options given below:**

- Which of the following is the greatest number?

A. 346752

B. 345672

C. 346725 - The smallest 4 digit number by using different digits with 7 is always at ones place is —————

A. 1027

B. 1207

C. 0127 - Write the numeral for Three lakh fifty three thousand five hundred.

A. 3, 05, 350

B. 3, 53, 500

C. 3, 35, 500 - How many lakhs are there in 1 crore?

A. 10

B. 100

C. 1000 - How many millions are there in 1 billion?

A. 10

B.100

C. 1000**Fill in the blanks:** - 1 crore = ———- million
- The Roman numeral for 100 is —————
- Division of a whole number by 0 is ———-
- The LCM of 9 and 4 is ————–
- The HCF of 23 and 45 is ————-
**Answer the following:** - Insert commas suitably and write number name according to Indian System of numeration: 87967321
- Rounds off to nearest tens, hundreds, thousands of the number 17654.
- Find 625 x 3759 x 8
- Write all the factors of 68
- Test the divisibility by 11 of the number 61809

**ANSWERS:**

- 346752
- 1027
- 3, 53,500
- 100
- 1000
- 10
- C
- Not defined
- 36
- 1
- 8, 79, 67, 321

Number names is Eight crore seventy nine lakh sixty seven thousand three hundred twenty one. - 17654

Nearest tens are 17650

Nearest hundreds are 17700

Nearest thousands are 18000 - (625 x 8) x 3759 = 5000 x 3759 = 18795000
- Factor pairs of 68 are 1 x 68, 2 x 34 and 4 x 17

Factors are 1, 2, 4, 17, 34 and 68. - Sum at odd place = 9 + 8 + 6 = 23

Sum at even place = 0 + 1 = 1

Difference = 23 – 1 = 22, which is a multiple of 11.

So it is divisible by 11.