# Chapter 2 Whole Numbers Expected Questions NCERT Class 6 Maths Solutions

EXPECTED QUESTIONS FOR ANNUAL EXAMINATION | NCERT CLASS 6 MATHEMATICS | WHOLE NUMBERS – Chapter 2

Answer the following (2 marks)

1. Write the successor and predecessor of 100199

2. Find the value of the following using suitable properties:

a) 345 x 97 + 345 x 3

b) 5467 x 154 – 5467 x 54

3. The school canteen charges 60 rupees for lunch and 15 rupees for snacks. How much money do you spend in 4 days on these things?

4. Find the product using suitable rearrangement: 5 x 465 x 20

5. Find using distributive property.

a) 3241 x 1001

b) 345 x 102

6. Find the value of 445 x 10 x 762 – 662 x 4450

7. Write the next three natural numbers after 10999.

8. Write the three whole numbers occurring just before 10001.

9. Write the properties used in each of the following:

a) 2 x 56 = 56 x 2

b) 4 x (5+8) = 4 x 5 + 4 x 8

c) 5 + (3+4) = (5+3) +4

10. Study the pattern. Write the next four steps.

6 x 2 -5 =7

7 x 3- 12 =9

8 x 4 – 21 =11

9 x 5 – 32 = 13

**ANSWERS:**

1. Successor of 100199 is 100200.

Predecessor of 100199 is 100198.

2. a) 345 x 97 + 345 x 3 = 345 x (97 +3) = 345 x100 = 34500

b) 5467 x 154 – 5467 x 54 = 5467 x (154 – 54) = 5467 x 100 = 546700.

3. The amount charged for lunch = 60 rupees

The amount charged for snacks = 15 rupees

Money spend in 4 days = 4 x (60 + 15) = 4 x 75 = 300 rupees.

4. 5 x 465 x 20 = 465 x (5 x 20) = 465 x 100 = 46500

5. a) 3241 x 1001 = 3241 x (1000 + 1) = 3241 x 1000 + 3241 x1

= 3241000 + 3241

= 3244241

b) 345 x 102 = 345 x (100 + 2)

= 345 x 100 + 345 x 2

= 34500 + 690

= 35190

6. 445 x 10 x 762 – 662 x 4450 = 4450 x 762 – 662 x 4450

= 4450 x (762 – 662)

=4450 x 100

= 445000

7. 11000, 11001, 11002

8. 10000, 9999, 9998

9. a) Commutativity under multiplication.

b) Distributivity of multiplication over addition.

c) Associativity under addition.

10. 10 X 6 – 45 = 15

11 X 7 – 60 = 17

12 X 8 – 77 = 19

13 X 9 – 96 = 21