# Simple Arithmetic & Mental Ability / Maths GK Questions

Simple Arithmetic & Mental Ability/ Maths GK Questions is about some model questions that you can expect for competitive examinations. Here you can find out Maths GK questions for competitive examinations.

Simple Arithmetic & Mental Ability/ Maths GK Questions
Expected Maths GK Questions for Competitive Examinations
Choose the correct answer:

1. If 2/5 of a number is 526, find the number?
A. 2630
B. 1315
C. 1052
2. 1000 + 0.001 = ———-
A. 1000.1
B. 1000.01
C. 1000.001
3. Convert to decimals: 80%
A. 4/5
B. 3/5
C. 2/5
4. Find the cost of fencing a rectangular garden of length 125m and breadth 75m, at the rate of Rs 25 per metre?
A. 5000
B. 10000
C. 15000
5. Sum of all angles of a polygon with 10 sides is ——— degree.
A. 1800
B. 1440
C. 720
6. Find the odd one out:
A. 8
B. 27
C. 63
7. The angle between the hour hand and minute hand of a clock when the clock time is 1 pm?
A.30 degree
B.60 degree
C.90 degree
8. Average of first 5 odd numbers is?
A.4
B.5
C.6
9. Ramu travelled 25m straight towards East. He turned left and travelled 15m straight. Then turned right and travelled 20m straight. Again he turned right and travelled 15 m straight. How far is he from the starting point?
A. 40m
B. 45 m
C. 50 m
10. If 60% of the students in a school are girls and number of boys is 1250, find the number of girls?
A. 1870
B. 3125
C. 750

ANSWERS:

1. 1315
2. 1000.001
3. 4/5
4. 10000
5. 1440
6. 63
7. 30 degree
8. 5
9. 45m
10. 1875

EXPLANATION:

1. Let the number be x.
Given 2/5 of x = 526
x = (526 x 5)/2 = 1315
2. 1000 + 0.001 = 1000.001
3. 80% = 80/100 = 8/10 = 4/5
4. Perimeter = 2 (l + b) = 2 (125 +75) = 2 x 200 = 400 m
Cost of fencing = 400 x 25 = 10000 rupees
5. The sum of angles of a polygon with n sides = (n – 2) x 180
(10 – 2) 180 = 8 x 180 = 1440 degree
6. 8 and 27 are perfect cubes.
63 is not a perfect cube
7. 30 degree
8. First 5 odd numbers are 1, 3, 5, 7 and 9
Average = (1+ 3 + 5 + 7 + 9)/5 = 25/5 = 5
9. 45m
10. Given 60% are girls. So the remaining 40% are boys
Let the total number of students be x
Then 40% of x = 1250
i.e., x = (1250 x 100)/40 = 3125
So the number of boys = 3125 – 1250 = 1875