# CBSE Class 10 Mathematics/Probability/Model Questions

**CBSE Class 10 Mathematics/Probability/Model Questions is about the extra questions that you can expect for Yearly examination. Here you can find out practice problems for Class 10 Mathematics. This worksheet is designed for CBSE Class 10 Mathematics Students.**

**CBSE Class 10 Mathematics/Probability – Chapter 15Extra Questions for Practice/Model QuestionsAnswer the following:**

**One card is drawn from a well shuffled deck of 52 cards. Calculate the probability that the card will**

a) Neither a jack nor an ace

b) Red king

c) A queen or a jack

d) Face card

e) Queen of diamonds

f) Black queen

g) Ace and black

h) Neither an ace nor a king

i) Neither a red card nor a black king

j) Jack of hearts

k) A spade

Solution:

a) The number of possible outcomes = 52

The number of favourable outcomes = 44

Probability (getting neither a jack nor an ace) = 44/52 = 11/13

b) Probability (getting a red king) = 2/52 = 1/26

c) Probability (getting a queen or a jack) = 4/52 + 4/52 = 8/52 = 2/13

d) Probability (getting a face card) = 12/52 = 3/13

e) Probability (getting a queen of diamonds) = 1/52

f) Probability (getting a black queen) = 2/52 = 1/26

g) Probability (getting an ace and black) = 2/52 = 1/26

h) Probability (getting neither an ace nor a king) = 44/52 = 11/13

i) Probability (getting neither a red card nor a black king) = 24/52 = 6/13

j) Probability (getting a jack of hearts) = 1/52

k) Probability (getting a spade) = 13/52 = ¼**The probability of an event of a random experiment lies in between ———–**

Solution: 0 and 1**One card is drawn from a well shuffled deck of 52 cards. Find the probability of getting**

a) 2 of spades

b) 10 of a black suit

Solution:

a) Number of favourable outcomes = 1

Probability (getting 2 of spades) = 1/52

b) Number of favourable outcomes = 2

Probability (getting 10 of a black suit) = 2/52 = 1/26**A die is thrown once. Find the probability of getting a number greater than 4?**

Solution:

Numbers greater than 4 are 5 and 6.

So number of favourable outcomes = 2

The number of possible outcomes = 6

Probability (getting a number greater than 4) = 2/6 = 1/3**If P (E) = 0.07, what is the probability of ‘not E’?**

Solution:

We know that P (E) + P (not E) = 1

P (not E) = 1- P (E) = 1 – 0.07 = 0.93