# CBSE Class 10 Mathematics/Probability

**CBSE Class 10 Mathematics/Probability – Chapter 15 is about the Model Questions that you can expect for Yearly Examination. Here you can find out practice problems for Class 10 Mathematics. This worksheet is designed for CBSE Class 10 Mathematics Students.**

**CBSE Class 10 Mathematics/Probability – Chapter 15Extra Questions for Practice/Model QuestionsAnswer the following:**

**A die is thrown once. What is the probability of getting:**

a) a perfect number

b) a perfect square composite number

c) an even composite number

d) a number which has at least two factors

e) at most 2

f) a number which is either a multiple of 2 or 3

g) a number which is not a factor of 12

h) an even number

i) a number greater than 3

j) a number between 3 and 6

k) a prime number

l) a number lying between 2 and 6

m) an odd number

n) a number greater than 4

o) a number less than or equal to 4

Answers:

a) Number of possible outcomes is 1, 2, 3, 4, 5 and 6.

The only perfect number in between 1 and 6 is 6

So number of favourable outcome is 1

Probability of getting a perfect number = 1/6

b) The only perfect square composite number is 4.

So the probability is 1/6

c) Even composite numbers are 4 and 6 only.

So number of favourable outcome is 2.

Probability of getting an even composite number = 2/6 = 1/3

d) The numbers which have at least two factors are 2, 3, 4, 5 and 6.

So number of favourable outcome is 5.

Probability of getting a number which has at least two factors = 5/6

e) Probability of getting at most 2= 2/6 = 1/3

f) A number which is a multiple of 2 or 3 are 2, 3, 4, and 6.

So number of favourable outcome is 4.

Probability = 4/6 = 2/3

g) A number which is not a factor of 12 are 5.

So number of favourable outcome is 1

Probability of getting a number which is not a factor of 12 = 1/6

h) Even numbers are 2, 4 and 6.

So number of favourable outcome is 3

Probability of getting an even number = 3/6 = ½

i) Numbers greater than 3 are 4, 5 and 6.

So number of favourable outcome is 3

Probability of getting a number greater than 3 = 3/6 = ½

j) Numbers between 3 and 6 are 4 and 5.

So number of favourable outcome is 2.

Probability of getting a number between 3 and 6 = 2/6 = 1/3

k) Prime numbers are 2, 3 and 5.

So number of favourable outcome is 3.

Probability of getting a prime number = 3/6 = ½

l) Numbers lying between 2 and 6 are 3, 4 and 5.

So number of favourable outcome is 3

Probability of getting a number lying between 2 and 6 = 3/6 = ½

m) Odd numbers are 1, 3 and 5.

So number of favourable outcome is 3.

Probability of getting an odd number = 3/6 = ½

n) Numbers greater than 4 are 5 and 6.

So number of favourable outcome is 2

Probability of getting a number greater than 4 = 2/6 = 1/3

o) Numbers less than or equal to 4 are 1, 2, 3 and 4

So number of favourable outcome is 4.

Probability of getting a number less than or equal to 4 = 4/6 = 2/3