# Maths GK/General Knowledge Questions for Competitive Exams.

MATHS GK
Maths General Knowledge Questions for competitive exams –Part 3

1. The angle measurement of a clock when the clock time is 6 pm.
A. 170
B. 180
C. 190

2. If we divide half of half by half then the quotient will be —————
A. ¼
B. 1/8
C. ½

3. The ratio between the number of boys and number of girls in a class is 3:4. If the numbers of girls are 24, what will be the number of boys?
A. 6
B. 18
C. 20

4. What number comes next?
125, 64, 27, 8 —————-
A. 1
B. 2
C. 3

5. The multiplicative inverse of -1/5 is ————-
A. -5
B. 5
C. 1/5

6. The sum of first 50 natural numbers is —————
A. 1250
B. 1275
C. 1290

7. The average of all prime numbers between 1 and 10 is ————-
A. 4
B. 4.25
C. 4.50

8. If 5 % of a number is 20, then 20 % of that number is ——
A. 80
B. 400
C. 200

9. Which is greater?
A. 0.07
B. 0.707
C. 0. 0707

10. The difference between the smallest four digit number and the greatest three digit number is ————
A. 1
B. 0
C. 111

11. Manu’s father’s age is 6 years more than 2 times Manu’s age. If his father is 48 years old, Manu’s age will be —————–
A. 21
B. 20
C.19

12. Find the value of 8 + 2 x 5 – 3 x 1
A. 13
B. 15
C. 17

13. If A: B = 3: 5, B: C= 3:5, then A: C = ——————
A. 25:9
B. 9: 25
C. 3:5

14. 10 th term of the following sequence 2, 7, 12 ——————-is ————-
A. 45
B. 47
C. 49

15. How many prime numbers are there between 50 and 100?
A. 9
B. 10
C. 11

1. 180

2. ½

3. 18
(Given ratio = 3:4
Number of boys = 3x
Number of girls = 4x
Given number of girls = 24
Therefore, 4x = 24
x = 6
Number of boys = 3x = 3 x 6 = 18)

4. 1
(Cube of 5 is 125
Cube of 4 is 64
Cube of 3 is 27
Cube of 2 is 8
Cube of 1 is 1)

5. -5

6. 1275
(Sum of first n natural numbers = n (n+1) /2 = 50 x 51/2 = 1275)

7. 4.25
(Prime numbers between 1 and 10 are 2, 3, 5, and 7.
Average = ¼ (2+3+5+7) = 17/4= 4.25

8. 80
(Let the number be x
Given 5 % of x are 20.
So 5x/100 =20
x = 2000/5 = 400
Then 20 % of 400 = 20 x 400/100 = 80)

9. 0.707

10. 1
(Smallest four digit number is 1000 and greatest three digit number is 999.Their difference is 1000 – 999 = 1)

11. 21
(Let Manu’s age be x.
Manu’s father’s age = 6+2x
Given, 6+2x = 48
Therefore, 2x = 48 – 6 = 42
x = 21)

12. 15 (Use BODMAS)

13. 9:25

14. 47
(In the sequence 2, 7, 12………………, a = 2, d=5 and n=10.
10th term = a+ (n-1) d = 2 + (10-1)5 = 2 + 45 = 47)

15. 10

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