# Integers – Class 7

**IMPORTANT QUESTIONS FOR CBSE CLASS 7 MATHEMATICS**

**Integers – Chapter 1**

**Answer the following:**

1. Write down a pair of integers whose:

a) Sum is -5

b) Difference is -15

2. Write down a pair of negative integers whose difference gives 6.

3. Write a negative integer and a positive integer whose sum is -10.

4. What will be the sign of the product if we multiply together (-1) twelve times?

5. Find

a) (-1) x (-5) x (-4) x (-6)

b) (-456) x (-1)

6. Find the product using suitable properties.

a) 34 x (-45) + (-45) x (-24)

b) 23 x (-25) x (-4) x (-10)

7. Replace the blank with an integer to make it a true statement?

a) (-1) x ——– = 45

b) ——— x (-4) = -28

8. Verify (-2) x [(-4) + (-3)] = [(-2) x (-4)] + [(-2) x (-3)]

9. Determine the integer whose product with (-1) is

a) -25

b) 25

10. Evaluate

a) (-25) divided by (-5)

b) (-36) divided by 4

**ANSWERS**:

**1. a) (-3) and (-2). (Answers may vary)**

**b) 5 and 20, since 5 – 20 = -15.**

**2. (-4) and (-10), since (-4) – (-10) = (-4) + (+10) =+6**

**3. (-20) and (10), since (-20) + (10) = (-10).**

**4. Since 12 is an even number its product must be positive.**

**5. a) 120**

**b) 456**

**6. a) (-45) [34 + (-24)] = (-45) x 10 = -450 **

**b) [(-25) x (-4)][23 x (-10)] = 100 x (-230) = -23000.**

**7. a) (-1) x (-45) = 45**

**b) 7 x (-4) = -28**

**8. LHS = (-2) x [(-4) + (-3)] = (-2) x (-7) = 14**

**RHS = [(-2) x (-4)] + [(-2) x (-3)]**

**= 8 + 6 = 14.**

**Therefore LHS = RHS, so verified.**

**9. a) (-1) x 25 = -25**

**b) (-1) x (-25) = 25**

**10. a) 5**

**b) -9**