# CBSE Class 4 Mathematics/ Fields and Fences/Model Questions/ Worksheet

**CBSE Class 4 Mathematics/ Fields and Fences /Worksheet is about the Model Questions that you can expect for Yearly Examination. Here you can find out practice problems for Class 4 Mathematics.**

**CBSE Class 4 Mathematics/ Fields and Fences – Chapter 13Extra Questions for Practice/WorksheetsChoose the correct answer:**

**Length of one side of a square is 6 cm. Then its perimeter is ————–**

A. 36 cm

B. 12 cm

C. 24 cm**Area of a rectangle is 36 sq cm and length is 9 cm. Find its breadth?**

A. 9 cm

B. 6 cm

C. 4 cm**The length of the boundary of a closed figure is called ——–**

A. Volume

B. Area

C. Perimeter**Area of a rectangle 5 cm long and 3 cm wide is ——— sq cm.**

A. 8

B. 10

C. 15**Area of a square with side 3m is ———-**

A. 12

B. 9

C. 6

Fill in the blanks:**The perimeter of a triangle of sides 4m, 3m and 2m is ———****The amount of surface enclosed within a closed figure is called ————–****Unit of area is ————–****The perimeter of a square of sides 5 cm is ————****A square has a boundary of 12 cm. What will be the length of each side?**

Answer the following:**A square wall has a perimeter of 100 m. What is the side of the wall? Find its area?****A rectangular garden is 150m long and 50m wide. Find its Perimeter?****A square carom board has a perimeter of 420 cm. Find the length of each side?****Find the perimeter of a rectangle whose length and breadth are respectively 12 cm and 9 cm.****A rectangular field is 48 m long and 20m broad. Find the cost of fencing the field at the rate of Rs 50 per metre?**

**ANSWERS:**

**24 cm****4 cm****Perimeter****15 sq cm****9 sq cm****9m****Area****Square cm/m/km****20 cm****3 cm****Perimeter of a square = 100m**

Length of side of the wall = 100/4 = 25m

Area = Side X Side = 25 x 25 = 625 sq m**Length = 150m**

Breadth = 50m

Perimeter = 150 + 50 + 150 + 50 = 400m**Perimeter of a square = 420 cm**

Length of each side = 420/4 = 105 cm**Length = 12 cm**

Breadth = 9 cm

Perimeter = 12 + 9 + 12 + 9 = 42 cm**Length = 48m**

Breadth = 20m

Perimeter = 48 + 20 + 48 + 20 = 136m

Cost of fencing = 136 x 50 = 6800 rupees