# Mensuration – Class 6 Maths/Exercise 10.3/ NCERT Solutions.

**Chapter 10 of CBSE/NCERT Class 6 Mathematics is about Mensuration. Here in this lesson you can find out text book solutions of Exercise 10.3**

**CBSE CLASS 6 MATHEMATICSMENSURATION – Chapter 10 /Exercise 10.3**

- Find the areas of the rectangles whose sides are:

a) 3 cm and 4 cm

b) 12 m and 21 m

c) 2 km and 3 km

d) 2m and 70 cm

Answer:

a) Area of a rectangle = length X breadth

Given length = 3 cm

Breadth = 4 cm

Area = 3 X 4 = 12 sq cm

b) Area = length X breadth = 12 X 21 = 252 sq cm

c ) Area = 2 X 3 = 6 sq km

d) Area = length X breadth

Length = 2m = 200 cm

Breadth = 70 cm

Area = 200 X 70 = 14000 cm = 1.40 sq m - Find the areas of the squares whose sides are:

a) 10 cm

b) 14 cm

c) 5 m

Answer:

Area of a square = side X side

a) Area = 10 X 10 = 100 sq cm

b) Area = 14 X 14 = 196 sq cm

c) Area = 5 X 5 = 25 sq m - The length and breadth of three rectangles are as given below:

a) 9 m and 6 m

b) 17 m and 3 m

c) 4 m and 14 m

Which one has the largest area and which one has the smallest?

Answer:

a) Area = length X breadth = 9 X 6 = 54 sq m

b) Area = length X breadth = 17 X 3 = 51 sq m

c) Area = length X breadth = 4 X 14 = 56 sq m

It can be seen that (c) has the largest area and (b) has the smallest area. - The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden?

Ans:

Given Area = 300 sq m

Length = 50 m

Width = Area /length = 300 / 50 = 6m - What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of Rs 8 per hundred sq m?

Answer:

Here we want to find out the area of the given plot.

Given length = 500 m

Breadth = 200m

Area = 500 X 200 = 100000 sq m

Cost of tiling per hundred sq m = Rs 8

Cost of tiling per 100000 sq m = 1000 X 8 = 8000 rupees - A table-top measures 2 m by 1m 50 cm. What is its area in square meters?

Answer:

Given length = 2m = 200 cm

Breadth = 1m 50 cm = 150 cm

Area = length X breadth = 200 X 150 = 30000 sq cm = 3 sq m - A room is 4 m long and 3 m 50 cm wide. How many square meters of carpet is needed to cover the floor of the room?

Answer:

Given length = 4 m = 400 cm

Breadth = 3 m 50 cm = 350 cm

Area = length X breadth = 400 X 350 = 140000 sq cm = 14 sq m - A floor is 5 m long and 4 m wide .A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted?

Answer:

First find the area of the floor.

Given length = 5 m and breadth = 4 m

Area = 5 X 4 = 20 sq m

Then find the area of the carpet.

Given side of the square carpet = 3 m

Area of the carpet = 3 X 3 = 9 sq m

Area of the floor that is not carpeted = 20 – 9 = 11 sq m - Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Answer:

Given length of the land = 5 m

Breadth = 4 m

Area of the land = 5 X 4 = 20 sq m

Area of the flower bed of side 1m = 1 X 1 = 1 sq m

Area of such 5 flower beds = 5 X1 = 5 sq m

Area of the remaining part of the land = 20 – 5 = 15 sq m - By splitting the following figures into rectangles, find their areas (The measures are given in centimeters)

a) Area of first rectangle = 4 X 2 = 8 sq cm

Area of second rectangle = 6 X 1 = 6 sq cm

Area of third rectangle = 3 X 2= 6 sq cm

Area of fourth rectangle = 4 X 2 = 8 sq cm

Total area of the figure = 8 + 6 + 6 + 8 = 28 sq cm

b) Area of first rectangle = 3 X 1 = 3 sq cm

Area of second rectangle = 3 X 1 = 3 sq cm

Area of third rectangle = 3 X 1 = 3 sq cm

Total area of the figure = 3 + 3+ 3 = 9 sq cm - Split the following shapes into rectangles and find their areas.

(The measures are given in centimeters)

a) Area of first rectangle = 12 X 2 = 24 sq cm

Area of second rectangle = 8 X 2 =16 sq cm

Total area of the figure = 24 + 16 = 40 sq cm

b) The given figure can be split into 5 equal squares each of side 7 cm.

Area of a square = side X side = 7 X 7 = 49 sq cm

Therefore, the required area = 49 X 5 = 245 sq cm

c) Area of the first rectangle = 5 X 1 = 5 sq cm

Area of the second rectangle = 4 X 1 = 4 sq cm

Total area of the figure = 5 + 4 = 9 sq cm - How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively?

a) 100 cm and 144 cm

b) 70 cm and 36 cm.

Answer:

a) Total area of the rectangular region = 100 X 144 = 14400 sq cm

Area of one tile = 12 X 5 = 60 sq cm

Number of tiles required = 14400 /60 = 240 tiles

b) Total area of the rectangular region = 70 X 36 = 2520 sq cm

Area of one tile = 12 X 5=60 sq cm

Number of tiles required = 2520 / 60 = 42 tiles

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