# Comparing Quantities | Class 7 Maths Important Questions For Exam

IMPORTANT QUESTIONS FOR CBSE EXAMINATION | CLASS 7 MATHEMATICS

COMPARING QUANTITIES – Chapter 8

Answer the following (2 mark):

1. Find the ratio of each of the following in simplest form:

a) 5 rupees to 50 paise

b) 27 cm to 9m

2. Convert the following to fraction in lowest term:

a) 20 %

b) 40%

3. Out of 32 students, 8 are absent. What percent of the students are absent?

4. A shop has 500 parts, out of which 5 are defective. What percent are defective?

5. 75% of what number is 15?

6. Find 25% of 700 rupees?

7. Divide 300 rupees between Manu and Sonu so that they get 40% and 60% of them respectively.

8. Convert each part of the ratio to percentage:

a) 3:2

b) 5:3:2

9. If the cost of 15 notebooks is 450 rupees, what will be the cost of 8 such notebooks?

10. Convert the given decimals to fractions and percents?

a) 0.45

b) 0.04

ANSWERS:

1. a) 5 rupees = 500 paise

Ratio = 500:50 = 10:1 (50 is a common factor)

b) 9m = 900 cm

27:900 = 3:100 (9 is a common factor)

2. a) 20% = 20/100 = 1/5 (20 is a common factor).

b) 40% = 40/100 = 2/5 (20 is a common factor).

3. Percentage of the students who are absent = 8 x 100/32 = 800/32 = 25%.

4. Percentage that are defective = 5 x 100/ 500 = 500/500 = 1%.

5. Let the number be x.

75% of x = 15

75 x = 15 x 100

75 x = 1500

x = 1500/75 = 20.

6. 25% of 700 rupees = 25 x 700/100 = 25 x 7 = 175 rupees.

7. 40 % of 300 = 40 x 300 /100 = 40 x3 = 120.

60% of 300 = 60 x 300/ 100 = 60 x 3 = 180.

8. a) Sum of the parts = 3 + 2 = 5

3 x 100/ 5 = 3 x 20 = 60%.

2 x 100 / 5 = 2 x 20 = 40%.

b) Sum of the parts = 5 + 3 + 2 = 10

5 x 100/ 10 = 5 x 10 = 50%

3 x 100 / 10 = 3 x 10 =30%

2x 100 / 10 = 2 x 10 = 20%.

9. Cost of 15 notebooks = 450 rupees.

Cost of one notebook = 450 / 15 = 30 rupees.

Cost of 8 notebooks = 30 x 8 = 240 rupees.

10. a) 0.45 = 45/100 = 45%.

b) 0.04 = 4/100 = 4%.