# Class 5 Maths | Area And Its Boundary Practice Problems

Test book solutions of the chapter Area and Its Boundary can be found here.

Given below are practice problems that you can attempt to boost your understanding of this chapter. Here at learnmathsonline.org, we have textbook solutions and practice problems for all chapters of CBSE Class 5 Maths.

## Area and its boundary – Model Questions | Class V – Mathematics

1. Find the area of rectangle whose length is 20 cm and breadth is 5 cm.

2. Find the perimeter of a rectangular garden whose length is 120 cm and breadth is 90 cm.

3. A square carrom board has a perimeter 320 cm. What is its area?

4. Area of a rectangle is 80 square cm and length is 10 cm. Find its breadth and perimeter.

5. A rectangular field is 24 m long and 20 m broad. Find the cost of fencing the field at the rate of Rs 30 per meter.

6. Find the area and perimeter of a square of side 25 cm.

7. An athlete takes 10 rounds of a rectangular park, 50 m long and 25 m wide. Find the total distance covered by him.

8. Find the cost of fencing a rectangular park of length 250 m and breadth 175 m at the rate of Rs 12 per meter.

9. Find the perimeter of a regular pentagon with each side measuring 3 cm.

10. Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?

1. Given length = 20 cm

Area of a rectangle = length x breadth
Area = 20 x 5 = 100 square cm

2. Given length = 120 cm

Perimeter of rectangle = 2 x (length + breadth)
Perimeter = 2 x (120 + 90)
= 2 x 210
= 420 cm

3. Perimeter of a square = 320 cm

Length of each side = 320 / 4 = 80 cm
Area of the square = Side x Side = 80 x 80 = 6400 square cm

4. Given area of a rectangle = 80 square cm

Length = 10 cm
Area of a rectangle = Length x Breadth
Breadth = 80 / 10 = 8 cm
Perimeter of the rectangle = 2 x (length + breadth)
Perimeter = 2 x (10 + 8) = 2 x 18 = 36 cm

5. Given length = 24 m

Perimeter of the rectangle = 2 x (length + breadth)
Perimeter = 2 x (24 + 20)
= 2 x 44
= 88 m
Cost of fencing at the rate of Rs 30 per meter = 88 x 30 =Rs 2640

6. Given side of a square = 25 cm

Area of the square = side x side = 25 x 25 = 625 square cm
Perimeter = 4 x side = 4 x 25 = 100 cm

7. Given length = 50 m

Perimeter = 2 x (length + breadth)
Perimeter = 2x (50 + 25)
= 2 x 75
= 150 m
If he takes 10 rounds, then the total distance covered = 150 x 10 = 1500 m

8. Given length = 250m

Perimeter = 2 x (length + breadth)
Perimeter = 2 x (250 + 175)
= 2 x 425
= 850 m
Cost of fencing at the rate of Rs 12 = 850 x 12 = Rs 10200

9. Given the length of each side of a pentagon = 3 cm

Five sided figure is known as Pentagon.
Therefore, perimeter = 5 x 3 = 15 m

10. Given perimeter of a triangle = 36 cm

Lengths of two sides are 12 cm and 14 cm.
Length of third side = 36 – (12 + 14)
= 36 – 26
= 10 cm

### 6 Responses

1. Shubham says:

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• Priyesha says:

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2. Sai kamal Panda says:

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3. Saumya says:

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4. Saumya says:

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5. Shlok says:

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