CBSE Class 6 Mathematics Worksheets/Part 4/Half Yearly Examination
CBSE Class 6 Mathematics Worksheets is about some model questions that you can expect for half yearly examination. Here you can find out practice problems for class 6 Mathematics.
CBSE CLASS 6 MATHEMATICS WORKSHEETS/ Part 4/ Half Yearly Examination
Choose the correct answer from the options given below:
- Which of the following is the greatest number?
A. 346752
B. 345672
C. 346725 - The smallest 4 digit number by using different digits with 7 is always at ones place is —————
A. 1027
B. 1207
C. 0127 - Write the numeral for Three lakh fifty three thousand five hundred.
A. 3, 05, 350
B. 3, 53, 500
C. 3, 35, 500 - How many lakhs are there in 1 crore?
A. 10
B. 100
C. 1000 - How many millions are there in 1 billion?
A. 10
B.100
C. 1000
Fill in the blanks: - 1 crore = ———- million
- The Roman numeral for 100 is —————
- Division of a whole number by 0 is ———-
- The LCM of 9 and 4 is ————–
- The HCF of 23 and 45 is ————-
Answer the following: - Insert commas suitably and write number name according to Indian System of numeration: 87967321
- Rounds off to nearest tens, hundreds, thousands of the number 17654.
- Find 625 x 3759 x 8
- Write all the factors of 68
- Test the divisibility by 11 of the number 61809
ANSWERS:
- 346752
- 1027
- 3, 53,500
- 100
- 1000
- 10
- C
- Not defined
- 36
- 1
- 8, 79, 67, 321
Number names is Eight crore seventy nine lakh sixty seven thousand three hundred twenty one. - 17654
Nearest tens are 17650
Nearest hundreds are 17700
Nearest thousands are 18000 - (625 x 8) x 3759 = 5000 x 3759 = 18795000
- Factor pairs of 68 are 1 x 68, 2 x 34 and 4 x 17
Factors are 1, 2, 4, 17, 34 and 68. - Sum at odd place = 9 + 8 + 6 = 23
Sum at even place = 0 + 1 = 1
Difference = 23 – 1 = 22, which is a multiple of 11.
So it is divisible by 11.