# Mensuration/CBSE Class 6 Mathematics/Chapter 10/Worksheet

## Extra Questions for Practice/Model Questions

**Answer the following:**

- The area of a square plot is 3600 sq.cm. Find the length of each side?
- The length of a cardboard is 24cm and its breadth is ¼ of its length. Find its area and perimeter?
- The length and breadth of a rectangle are 35cm and 15cm respectively. Find its area and perimeter?
- The side of a square is 9cm. Find its area and perimeter?
- The area of a rectangle is 48 sq.cm. If its breadth is 8cm, find its length?
- The area of a square is 121 sq.cm. Find the length of each side?
- Find the perimeter of an equilateral triangle of length 7cm?
- Find the perimeter of an isosceles triangle of equal side 5cm and third side 8cm?
- The perimeter of a regular hexagon is 72 cm. Find the length of each side?
- Find the perimeter of a regular pentagon of side 7cm?
- Find the cost of fencing a rectangular park of length 8m and breadth 5m at 85 rupees per meter.
- Find the cost of fencing a square park of side 250m at the rate of 24 rupees per metre.
- A room is 4m 25cm long and 2m75cm wide. Find the area of the carpet needed to cover the floor?
- The perimeter of a triangle is 40cm. The length of two sides are 14cm and 12 cm, find the length of third side?
- Find the perimeter of a quadrilateral of sides 6cm, 7cm, 3cm and 2cm.

ANSWERS:

- Area = 3600 sq.cm

Side x Side = 3600

60 x 60 = 3600

Length of each side = 60cm - Length = 24cm

Breadth = ¼ of 24 = 6cm

Area = l x b = 24 x 6 = 144 sq.cm

Perimeter = 2 x (l + b) = 2 x (24 + 6) = 2 x 30 = 60cm - Length = 35cm

Breadth = 15cm

Area = l x b = 35 x 15 = 525 sq.cm

Perimeter = 2 x (l + b) = 2 x (35 + 15) = 2 x 50 = 100 cm - Side = 9cm

Area = side x side = 9 x 9 = 81 sq.cm

Perimeter = 4 x side = 4 x 9 = 36 cm - Area of a rectangle = 48 sq.m

Breadth = 8cm

Length = 48 divided by 8 = 6cm - Area = 121 sq.cm

Side x side = 121 sq.cm

11 x 11 = 121 sq.cm

Length of each side = 11 cm - Perimeter of an equilateral triangle = 3 x side = 3 x 7 = 21cm
- Perimeter = 5 + 5 + 8 = 18cm
- Perimeter of a regular hexagon = 72cm

Length of each side = 72 divided by 6 = 12 cm - Perimeter of a regular pentagon = 5 x side = 5 x 7 = 35 cm
- Length = 8m

Breadth = 5m

Perimeter = 2 x (l + b) = 2 x (8+5) = 2 x 13 = 26m

Cost of fencing = 26 x 85 = 2210 rupees - Perimeter = 4 x side = 4 x 250 = 1000 m

Cost of fencing = 24 x 1000 = 24000 rupees - Length = 4m 25cm = 4.25m

Breadth = 2m 75cm = 2.75m

Area = l x b = 4.25 x 2.75 = 11.6875 sq.m - Perimeter = 40cm

Length of third side = 40 – (14 + 12) = 40 – 26 = 14 cm - Perimeter = 6 + 7 + 3 + 2 = 18cm