Important Questions for CBSE Class 7 Mathematics/Integers – Chapter 1
Important Questions for CBSE Class 7 Mathematics/Integers – Chapter 1
Extra Questions for Practice/Model Questions
- Fill in the blanks:
a) (-18) + 0 = —–
b) (-3) + (-9) = —–
c) (-24) + 24 = —–
d) (-21) – (-20) = ————-
e) 20 – (-21) = ——— - Write down a pair of integers for the following:
a) Sum gives -5
b) Difference gives -3 - Find the product of:
a) (-3) x 0 x 5
b) (-1) x (-1) x (-1)
c) (-2) x (-6) x (-1) - In a game team A scored 10, -20, 30 and team B scored -30, 20, 10.Who scored more and by how much?
- Find the product using suitable properties:
a) 14 x (-20) + (-20) x (-24)
b) 2 x (-54) x (-50) - Determine an integer whose product with (-1) gives ——-
a) (-24)
b) 0
c) 24 - Divide 256 by (-16)
- Write all integers in between -4 and 4.
- Find:
a) [10 + (-2)] x 5
b) [2- (-5)] x 10 - Write the opposite of:
a) Deposit of 500 rupees
b) Going South
c) 5 degree Celsius below zero. - Write the property used here:
a) 12 x (10 x (-3)) = (12 x 10) x (-3)
b) 12 + (-34) = (-34) + 12
c) 12 x (10 + (-3)) = 12 x 10 + 12 x (-3) - Fill in the blanks:
a) —- x (-1) = -25
b) 23 x —- = -23
c) —– x (-21) = 21
Solution:
- a) -18
b) -12
c) 0
d) (-21) + 20 = -1
e) 20 + 21 = 41 - a) (-3) + (-2) = -5
b) 1 – 4 = 1 + (-4) = -3 - a) 0
b) -1
c) -12 - Score of Team A = 10 + (-20) + 30 = 40 + (-20) = 20
Score of Team B = (-30) + 20 + 10 = (-30) + 30 = 0
Team A scored more by 20. - a) 14 x (-20) + (-20) x (-24) = (-20) [14 + (-24)] = (-20) x (-10) = 200
b) 2 x (-54) x (-50) = [2 x (-50)] x (-54) = (-100) x (-54) = 5400 - a) (-1) x (-24) = 24
b) (-1) x 0 = 0
c) (-1) x 24 = -24 - -16
- Integers between -4 and 4 are -3, -2, -1, 0, 1, 2, 3.
- a) [10 + (-2)] x 5 = 8 x 5 = 40
b) [ 2 – (-5)] x 10 = (2 + 5) x 10 = 7 x 10 = 70 - a) Withdrawal of 500 rupees
b) Going North
c) 5 Degree Celsius above zero - a) Associative property
b) Commutative property
c) Distributive property - a) 25
b) -1
c) -1