# Linear Equations In One Variable – Class 8/Maths.

**Chapter 2 of NCERT/CBSE Class 8 Maths is about Linear Equations in One Variable. Here in this chapter you can find practice problems for this chapter.**

**CBSE CLASS 8 MATHEMATICS/Model QuestionsLinear Equations in One Variable – Chapter 2Choose the correct answer from the options given below:**

- Which of the following is a linear equation in one variable?

A. 2x

B. 3y -7z

C. x + y + z - The solution of the equation 2x – 3 = 7 is ———

A. 3

B. 5

C. 7 - Solve the equation: 3x = 12

A. 3

B. 4

C. 5 - Which of the following is an equation?

A. 3x + y

B. y + 3 = 10

C. 3xyz - The highest power of a variable in a linear equation is ——-

A. 0

B. 1

C. 2**Answer the following:** - Solve the equation: 5x – 9 = 16
- The perimeter of a rectangle is 16 cm and its width is 3cm. Find its length?
- Check whether the linear equation 17 + 6p= 5 is true for p = -2.
- The sum of two numbers is 26 and their difference is 14. Find the two numbers?
- Convert the following statements into equations and solve?

a) Subtract 5 from seven times a number x gives 16.

b) Twice a number x added to 5 gives 25.

**ANSWERS:**

- 2x
- 5
- 4
- y + 3 = 10
- 1
- 5x – 9 = 16

5x = 16 + 9

5x = 25

x = 25/5 = 5. - Given perimeter = 16 cm and width = 3 cm.

Let the length of the rectangle be x.

Then we know that perimeter = 2 (length + breadth)

Therefore, 16 = 2(x + 3)

16/2 = x + 3

8 = x + 3

x = 8 – 3 = 5 - LHS = 17 + 6p

Substitute p = -2, 17 + 6 (-2) = 17 + (-12) = 5 = RHS. - Let one number be x.

Other number = 26 – x

Given difference of these numbers is 14.

ie, x – ( 26 – x) = 14

x – 26 + x = 14

2x = 14 + 26 = 40

x = 40/2 = 20. - a) 7x – 5 = 16

7x = 16 + 5 = 21

x = 21/7 = 3

b) 2x + 5 = 25

2x = 25 – 5 = 20

x = 20/2 = 10.