# Mensuration – CBSE Class 6 Mathematics/Extra Questions for Practice/Worksheet/Model Questions

Answer the following:

- What is the length of the wooden strip required to frame a photograph of length and breadth 42cm and 34cm respectively.
- A rectangular piece of land measures 0.9km by 0.7km. Each side to be fenced with 4 rows of wires. What is the length of the wire needed?
- Find the perimeter of an equilateral triangle of side 7cm?
- Find the perimeter of an isosceles triangle with equal sides 9cm each and third side 5cm.
- A piece of string is 50cm long. What will be the length of each side if the string is used to form a regular pentagon?
- Find the perimeter of a triangle with sides measuring 12cm, 10cm and 8cm?
- Find the perimeter of a regular hexagon with each side measuring 7m?
- Find the side of a square whose perimeter is 40cm?
- Find the cost of fencing a square park of side 150m at the rate of 25 rupees per meter?
- Find the cost of fencing a rectangular park of length 150m and breadth 125m at the rate of 15 rupees per meter?
- Find the area of a rectangle whose sides are 7cm and 4cm?
- Find the area of a square whose sides are 12cm?
- The area of a rectangular garden is 40m long is 360 sq. meter. Find the width of the garden?
- A room is 5m long and 3m 50cm wide. How many square meter of carpet is needed to cover the floor of the room?
- The length of a cardboard is 27cm and its breadth is one third of its length. Find its area?

ANSWERS:

- Length = 42cm

Breadth = 34cm

Perimeter = 2 x (l + b) = 2 x (42 + 34) = 2 x 76 = 152cm - Length = 0.9km

Breadth = 0.7km

Perimeter = 2 x (l + b) = 2 x (0.9 + 0.7) = 2 x 1.6 = 3.2 km

Length of the wire needed for 4 rows = 3.2 x 4 = 12.8km - Perimeter = 3 x length of one side = 3 x 7 = 21 cm
- Perimeter = 9 + 9 + 5 = 23cm
- Given perimeter = 50cm

Length of each side = 50/5 = 10cm - Perimeter = 12 + 10 + 8 = 30cm
- Perimeter = 6 x side = 6 x 7 = 42m
- Side of a square = 40/4 = 10cm
- Perimeter = 4 x side = 4 x 150 = 600m

Cost of fencing = 600 x 25 = 15000 rupees - Length = 150m

Breadth = 125m

Perimeter = 2 x (l + b) = 2 x (150 + 125) = 2 x 275 = 550m

Cost of fencing = 550 x 15 = 8250 rupees - Area = l x b = 7 x 4 = 28 sq.cm
- Area = side x side = 12 x 12 = 144 sq.cm
- Length = 40m

Area = 360m

Width = Area/length = 360/40 = 9m - Length = 5m

Breadth = 3m 50cm = 3.50m

Area = l x b = 5 x 3.50 = 17.5 sq. meter - Length = 27cm

Breadth = 1/3 of 27 = 9cm

Area = l x b = 27 x 9 = 243 sq. meter