CBSE Class 10 Maths Chapter 5 Arithmetic Progressions MCQ

CBSE CLASS 10 MATHEMATICS / MCQ
Multiple Choice Questions / ARITHMETIC PROGRESSIONS – Chapter 5

1. Each of the numbers in the list 100, 70, 40, 10 ……………. Is called a ………………………

A. Term
B. Difference
C. Factor

2. A list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term is called an ……………………….

A. Geometric Progression
B. Arithmetic progression
C. Harmonic Progression

3. The common difference of the AP 6, 3, 0, -3 ……………….. is …………………………..

A. 3
B. -3
C. 0

4. Which of the following list of numbers does not form an AP?
A. 4, 10, 16, 22 ………………….
B. 1, -1, -3, -5…………………..
C. -2, 2, -2, 2, -2………………………

5. The n th term of the AP with first term ‘a’ and common difference ‘d’ is given by ——————-

A. a + (n-1) d
B. a – (n-1) d
C. a + (n-1) d

6. The 10th term of the AP 2, 7, 12 …………….is —————–?

A. 45
B. 47
C. 49

7. Which term of the AP 21, 18, 15 ……………….. is -81?

A. 33
B.35
C. 37

8. How many two digit numbers are divisible by 3?

A. 30
B. 60
C. 90

9. The sum of first n positive integers is given by ————–

A. n (n-1)/2
B. n (n+1)/2
C. n (n-1)/4

10. If a, b, c are in AP, then b = ———— and is called the arithmetic mean of a and c.

A. (a + c)/2
B. (a – c)/2
C. (a + b) /2

11. The sum of the first 1000 positive integers is —————-

A. 5050
B. 500500
C. 500050

12. The list of numbers -15, -10, -5, 0, 5 …………….. is —————

A. an AP with d = 5
B. an AP with d = -5
C. an AP with d = 0

13. In an AP if d = -5, n = 3 and nth term = 0 then a is —————-

A. 10
B. -10
C. 0

14. The sum of the first 22 terms of the AP 8, 3, -2 ………………… is ——————-

A. -989
B. -979
C. 979

15. If ‘l’ is the last term of the finite AP, then the sum of all terms of the AP is given by ———————

A. S = n (a + l)/2
B. S = n (a – l)/2
C. S = n (a +l)/4

ANSWERS:

1. Term
2. Arithmetic Progression
3. -3
4. -2, 2, -2, 2, -2………………
5. a + (n-1) d
6. 47
a + (n -1) d = 2 + (10 -1) 5 = 2 + 9 x 5 = 2 + 45 = 47
7. 35
nth term = a + (n-1) d
-81 = 21 + (n-1) (-3)
-81 = 21 + (-3n) +3
-81 = 24 -3n
-81 – 24 = -3n
-105 = -3n
n = 105/3 = 35
8. 30
The list of two digit numbers divisible by 3 is 12, 15, 18………………… 99
Here a = 12, d = 3, nth term = 99
99 = 12 + (n-1) 3
99 = 12 + 3n -3
99 – 12 + 3 = 3n
90 = 3n
n = 90/3 = 30
9. n (n+1)/2
10. (a + c)/2
11. 500500
12. an AP with d = 5
13. 10
nth term = a + (n-1)d
0 = a + (3 -1) (-5)
0 = a + (-10)
a = 10
14. -979
S = n/2 (2a + (n-1) d)
= 22/2 (2 x 8 + (22-1) (-5))
= 11(16 + -105)
= 11 x (-89)
= -979
15. S = n (a + l)/2

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