CBSE Class 6 Mathematics Worksheets/ Part 5

CBSE Class 6 Mathematics Worksheets is about some model questions that you can expect for annual/yearly examinations. Here you can find out practice problems for class 6 Mathematics.

CBSE CLASS 6 MATHEMATICS WORKSHEETS/ Part 5
For Yearly/Annual Examinations.
Choose the correct answer from the options given below:

  1. The place value of 7 in 346.87 is ————-
    A. Tenths
    B. Hundredths
    C. Thousandths
  2. The product of three times a variable x added to 4 and multiplied by 7 is —–
    A. 7(3x +4)
    B. 7(3 + 4x)
    C. 7(3+ x + 4)
  3. The side of a square with perimeter 30 m is ———-
    A. 7
    B. 7.5
    C. 10
  4. 5 m = ————- km
    A. 0.5
    B. 0.05
    C. 0.005
  5. The value of the variable x in 10 = x – 10 is —–
    A. 0
    B. 10
    C. 20
    Fill in the blanks:
  6. The perimeter of an equilateral triangle of length 7 cm is ——
  7. Manu is x years old at present. His age after 7 years is ————-
  8. The simplest form of the ratio 3: 12 is ————
  9. 2: 5 = —–: 15
  10. 5 mm = ——— cm
    Answer the following:
  11. Divide 500 rupees in the ratio 2:3
  12. Find the ratio of 3 m to 15 cm
  13. Anu spent 15.50 rupees for a pen and 5.50 rupees for an eraser. How much money did he spend in all?
  14. Madhu bought 10 notebooks for 200 rupees and Anil bought 7 notebooks for 126 rupees. Who got the notebooks cheaper? How much?
  15. Find the cost of fencing a rectangular garden of length 32 m and breadth 20 m at the cost of 15 rupees per metre?

ANSWERS:

  1. Hundredths
  2. 7(3x + 4)
  3. 7.5
  4. 0.005 km
  5. 20
  6. 21 cm
  7. x + 7
  8. 1: 4
  9. 6
  10. 0.5
  11. Sum of parts = 2 + 3 = 5
    So we can divide 500 rupees as follows:
    500 x 2/5 = 200 rupees
    500 x 3/5 = 300 rupees
  12. 3m = 300 cm
    Ratio is 300: 15 = 20: 1
  13. Money spent for a pen = 15.50 rupees
    Money spent for an eraser = 5.50 rupees
    Total money spent = 15.50 + 5. 50 = 21 rupees
  14. Cost of 10 notebooks = 200
    Cost of 1 notebook = 200/10 = 20 rupees
    Cost of 7 notebooks = 126
    Cost of 1 notebook = 126/7 = 18 rupees
    Therefore Anil got the notebooks cheaper.
  15. Given length = 32 m and breadth = 20 m
    Perimeter = 2 (l + b) = 2 (32 + 20) = 2 x 52 = 104 cm
    Cost of fencing = 104 x 15 = 1560 rupees

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