# Whole Numbers – Chapter 2/ Extra Questions for Practice.

**CBSE CLASS 6 MATHEMATICS**

**Whole Numbers – Chapter 2**

**Extra Questions for Practice – Short Answer Type Questions:**

**Answer the following (2 marks):**

**1. Write the successor of **

**i) 2099**

**ii) 100**

**2. Write the predecessor of **

**i) 1000**

**ii) 32098**

**3. Write the next three natural numbers after 2009.**

**4. Write the property of whole numbers used here:**

**(3 + 4) + 5 = 3 + (4+5)**

**5. Find using suitable properties:**

**i) 25 x 657 x 4**

**ii) 625 x 43256 x 16.**

**6. Simplify using suitable properties:**

**i) 243 x 45 + 55 x 243.**

**ii) 452 x 125 – 452 x 25.**

**7. Find using Distributive property:**

**i) 423 x 101**

**ii) 436 x 1001**

**8. Write the property of whole numbers used here:**

**i) 2 x 45 x 65 = 65 x 45 x 2**

**ii) 43 + 236 +65 = 236 + 65 + 43**

**9. How many whole numbers are there between 30 and 39?**

**10. Which of the following statements are true and which are false?**

**i) Zero is the smallest natural number.**

**ii) Zero is the smallest whole number.**

**iii) All natural numbers are whole numbers.**

**iv) All whole numbers are natural numbers.**

**ANSWERS:**

**1. i) 2099 +1 = 2100**

**ii) 100 +1 = 101**

**2. i) 1000 – 1 = 999**

**ii) 32098 – 1 = 32097**

**3. 2010, 2011, 2012.**

**4. Associativity under addition.**

**5. i) (25 x 4) x 657 = 100 x 657 = 65700.**

**ii) (625 x 16) x 43256 = 10000 x 43256 = 432560000.**

**6. i) 243 (45 + 55) = 243 x 100 = 24300.**

**ii) 452 (125 – 25) = 452 x 100 = 45200.**

**7. i) 423 (100 +1) = 423 x 100 + 423 x 1= 42300 + 423 =42723.**

**ii) 436 (1000 +1) = 436 x1000 + 436 x 1 = 436000 + 436 = 436436.**

**8. i) Commutativity under Multiplication.**

**ii) Commutativity under Addition.**

**9. There are 8 whole numbers between 30 and 39.**

**10. i) False**

**ii) True**

**iii) True**

**iv) False.**