# Comparing Quantities – Class 8/Maths

**Chapter 8 of CBSE/NCERT Class 8 Mathematics is about comparing quantities. Here in this lesson you can find out practice problems for this lesson.**

**CBSE CLASS 8 MATHEMATICSComparing Quantities – Chapter 8/ WorksheetsFill in the blanks:**

- The ratio of 50 paise to Rs 2 is —————
- ————- is a reduction given on the Marked Price of the article.
- An item marked at Rs 340 is sold for Rs 324. What is the discount?
- ————– is the amount which we pay when we buy items.
- ————— is the extra money paid by institutions like banks or post offices on money deposited with them.
**Answer the following:** - The price of a TV was Rs 24000 last year. It has increased by 15% this year. What is the price now?
- Covert ratio to per cent; 2:3:5.
- 36% of 25 students are interested to play Football. How many students are interested to play Football?
- The cost of a frock at a shop was Rs 450. The sales tax charged was 5%. Find the bill amount?
- A skirt bought for Rs 250 and sold at Rs 150. Find the loss per cent?

**ANSWERS:**

- 1:4
- Discount
- 16
- Sales tax
- Interest
- First find out the 15% of 24000 = 15 x 24000/100 = 3600

New price = Old price + Increase = 24000 + 3600 = 27600 - Sum of the parts = 2 + 3 + 5 = 10

2/10 x 100% = 20%

3/10 x 100% = 30%

5/10 x 100% = 50% - Here we can find out 36% of 25 = 36 x 25/100 = 9 students
- Original price (CP) = Rs 450

Sales tax in rupees = 5% of its CP = 5 x 450/100 = 22.5

Bill amount = CP + Sales tax = 450 + 22.5 = 472.5 - Here CP = 250, SP = 150

Since CP> SP, then there is a loss = 250 -150 = 100 rupees

Loss per cent = Loss x 100/CP = 100 x 100/250 = 40%.

thanx for this piece of shit

THANX